(x^2+1)(x^2+3x+2)=0

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Solution for (x^2+1)(x^2+3x+2)=0 equation: 


Simplifying
(x2 + 1)(x2 + 3x + 2) = 0

Reorder the terms:
(1 + x2)(x2 + 3x + 2) = 0

Reorder the terms:
(1 + x2)(2 + 3x + x2) = 0

Multiply (1 + x2) * (2 + 3x + x2)
(1(2 + 3x + x2) + x2(2 + 3x + x2)) = 0
((2 * 1 + 3x * 1 + x2 * 1) + x2(2 + 3x + x2)) = 0
((2 + 3x + 1x2) + x2(2 + 3x + x2)) = 0
(2 + 3x + 1x2 + (2 * x2 + 3x * x2 + x2 * x2)) = 0
(2 + 3x + 1x2 + (2x2 + 3x3 + x4)) = 0

Combine like terms: 1x2 + 2x2 = 3x2
(2 + 3x + 3x2 + 3x3 + x4) = 0

Solving
2 + 3x + 3x2 + 3x3 + x4 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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